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0=-0.02x^2+95x-1500
We move all terms to the left:
0-(-0.02x^2+95x-1500)=0
We add all the numbers together, and all the variables
-(-0.02x^2+95x-1500)=0
We get rid of parentheses
0.02x^2-95x+1500=0
a = 0.02; b = -95; c = +1500;
Δ = b2-4ac
Δ = -952-4·0.02·1500
Δ = 8905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{8905}}{2*0.02}=\frac{95-\sqrt{8905}}{0.04} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{8905}}{2*0.02}=\frac{95+\sqrt{8905}}{0.04} $
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